Instantaneous Velocity \(v(t)\) can be found by plugging in time (t) into the derivative of the time function \((v)\) considering the time function is \((x)\).
\(x = \underline{-2t^{2} - 3}\)What is the instantaneous velocity at 2 seconds in the following graph function?
\(v = \dfrac{d}{dx}[x] = \dfrac{d}{dx}[-2t^{2} - 3] = -4t\)
\(v(t) = -4(2) = -8\,m/s\)
