\(where\)
\(P = permutation \)
\(n = total \,\,number\,\,in\,\,set\)
\(r = number\,\, of \,\,items\,\, to \)
\(choose\,\, and \,\,arrange\)
ex. a
How many 3-note permutations can be made from a snare, bass drum, and tom note, without repetition?
\(P1: S-B-T\)
\(P2: S-T-B\)
\(P3: T-S-B\)
\(P4: T-B-S\)
\(P5: B-T-S\)
\(P6: B-S-T\)
\(P = 6\)
\(Proven\,\,via\,\,formula:\)
\(P(n, r) = \dfrac{n!}{(n - r)!}\)
\(P(3, 3) = \dfrac{3!}{(3 - 3)!} = \dfrac{3!}{(0)!} = \dfrac{6}{1} = 6\)
ex. b
What is the number of combinations in ex. a? What big idea do we see?
\(Proven\,\,by\,\,formula:\)There is only 1 combination. This is because all those permutations are simply rearrangements of the same items.
\(C(n, r) = \dfrac{n!}{r!(n - r)!}\)
\(C(3, 3) = \dfrac{3!}{3!(3 -3)!} = \dfrac{3!}{3!(0)!} = \)
\(\dfrac{6}{6(1)} = 1\)
