Finding the x and y Intercepts of Any Function
Posted: Thu Jun 25, 2026 7:18 pm
Finding the x and y intercepts is as simple as plugging 0 into the "other" variable.
But x or y variables to plug-in must be in the numerator.
\(y = \dfrac{4x + 3}{2x - 3}\)ex. a
What are the x intercepts?
\(0 = \dfrac{4x + 3}{2x - 3} \)
\((2x - 3) 0 = \dfrac{4x - 3}{2x - 3}(2x - 3)\)
\(0 = \dfrac{(4x + 3)}{1}\)
\(0 = 4x + 3 \)
\(0 - 3 = 4x + 3 - 3\)
\(-3 = 4x\)
\(-\dfrac{3}{4} = \dfrac{4x}{4}\)
\(-\dfrac{3}{4} = x\)
x intercept is \((-\dfrac{3}{4}, 0)\).
\(y = 5x^{2} - x + 5\)ex. a
\(y = 5(0)^{2} - (0) + 5\)
\(y = 5\)