\(ex.\,\,a\)Finding the x and y intercepts is as simple as plugging 0 into the "other" variable.
\(What\,\,is\,\,the\,\,x\,\,intercept\,\, or\,\, x\,\, intercepts?\)
\(y = \dfrac{4x + 3}{2x - 3}\)
\(0 = \dfrac{4x + 3}{2x - 3} \)
\(0 = \dfrac{(2x - 3)(4x + 3)}{1}\)
\(0 = 2x - 3 \)
\(0 + 3 = 2x - 3 + 3\)
\(3 = 2x\)
\(\dfrac{3}{2} = \dfrac{2x}{2}\)
\(\dfrac{3}{2} = x\)
\(0 = 4x + 3\)
\(0 - 3 = 4x + 3 - 3\)
\(-3 = 4x\)
\(\dfrac{-3}{4} = \dfrac{4x}{4}\)
\(\dfrac{-3}{4} = x\)
\(therefore\,\,the \,\,x\,\,interecepts\,\,are:\)
\((\dfrac{3}{2}, 0) \,\,and\,\, (\dfrac{-3}{4}, 0)\)
