\(Way\,\,no.\,\,1\)The first way involves dividing everything by the term connected to x
\(3x + 4 = 11\)
\(\dfrac{3x}{3} + \dfrac{4}{3} = \dfrac{11}{3}\)
\(x + \dfrac{4}{3} = \dfrac{11}{3} \)
\(x + \dfrac{4}{3} - \dfrac{4}{3} = \dfrac{11}{3} - \dfrac{4}{3}\)
\(x = \dfrac{7}{3}\)
\(Way\,\,no.\,\,2\)
\(3x + 4 = 11\)
\(3x + 4 - 4 = 11 - 4\)
\(3x = 7\)
\(\dfrac{3x}{3} = \dfrac{7}{3}\)
\(x = \dfrac{7}{3}\)
\(Way\,\,no.\,\,3\)
\(3x + 4 = 11\)
\(3x + 4 - 11 = 11 - 11\)
\(3x - 7 = 0\)
\(3x - 7 + 7 = 0 + 7\)
\(3x = 7\)
\(\dfrac{3x}{3} = \dfrac{7}{3}\)
\(x = \dfrac{7}{3}\)
