\(3x \ge 4\)
\(x \ge \dfrac{4}{3}\)
\(\dfrac{4}{3} = 1.3\)
\([1.3, \infty)\)
The interval has a bracket, not a parentheses, on the left to show an interval going right from 1.3 to infinity and including 1.3
Not Shown on Post
The arrow representing the interval is going right, to infinity, from 1.3 with a solid circle at 1.3, due to 1.3 being in the interval.
\(ex. b\)
\(-5x \ge 15\)
\(x \le -\dfrac{15}{3}\)
\(x \le -3\)
\((-\infty, 3]\)
