Integral Substitution

[Jason]

\(ex. a\)

\(u = 3x + 1\)

\(du = 3 dx, \dfrac{du}{3} = dx\)

\(\int 4(3x + 1)^{9} dx\)

\(\int 4(u)^{9} \dfrac{du}{3} \)

\(4\dfrac{u^{10}}{10(3)} =\)

\(4\dfrac{(3x+1)^{10}}{10(3)}\)