Finding a Discontinuity in a function, also known as a "hole", involves factoring a function, if possible, and looking for removable factors
This factor is set to 0 and solved for x, and next, to find the y coordinate of the discontinuity, the removable factors are taken out and the x value is plugged into what's left.
What is the discontinuity in the following function?
\(\dfrac{(x + 1)(x - 1)}{(x + 1)}\)
\((x + 1) = 0\)The x part of the discontinuity is:
\(x = -1\)
\(y = (x - 1)\)
\(y = ((-1) - 1)\)
\(y = -2\)
