See Part I: viewtopic.php?p=1038
\(| 4 + x | \leq 1 \)ex. a
What is the solution to the linear absolute value inequality? How do you express in interval notation?
\(-1 \leq 4 + x \leq 1\)
\(-1 - 4 \leq 4 - 4 + x \leq 1 - 4\)
\(-5 \leq x \leq -3\)
\([-5, -3]\)
\(|x - 1| > 1\)ex. b
\(x - 1 > 1\)
\(x - 1 + 1 > 1 + 1\)
\(x > 2\)
\(x - 1 < -1\)
\(x - 1 + 1 < - 1 + 1 \)
\(x < 0\)
\((-\infty, 0) \cup (2, \infty)\)
