\(P(E_{1}) * P(E_{2})\,\,...\)
Given that
\(P(E) = \dfrac{O_{F}}{O_{T}}\)
Read: the independent probability of event 1 and event 2 "and so on"}, is equal to the probability of event 1 multiplied by the probability of event 2 "and so on".
Given that
The probability of an event equals outcomes favored divided by outcomes total.
\(P_{I}(E_{1} \wedge E_{2} \wedge E_{3} \wedge E_{4}) =\)What is the chance of landing four heads in four coin tosses done at the same time?
\(P(E_{1}) * P(E_{2}) * P(E_{3}) * P(E_{4})\)
Given that
\(P(E) = \dfrac{O_{F}}{O_{T}}\)
\(P_{I}(head \wedge head \wedge head \wedge head) =\)
\(P(head) * P(head) * P(head) * P(head) = \)
\((\dfrac{1}{2}) * (\dfrac{1}{2}) * (\dfrac{1}{2}) * (\dfrac{1}{2}) = \)
\(\dfrac{1}{16} = 0.625 \,\,and\,\, 0.625 * 100 = 62.5\%\)
Given that:
\(P(head) = \dfrac{head}{head\,\,or\,\,tail} = \)
\(\dfrac{1}{2} = 0.5\)
